\( \DeclareMathOperator{cosec}{cosec} \)
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This video on Deduction is from Revision Village and is aimed at students taking the IB AA Maths Standard level course
Example, Show that the algebraic generalisation of the following is true.
$$ \frac{1}{m+1} + \frac{1}{m^2+m} \equiv \frac{1}{m} $$Let's start by finding a common denominator for the left-hand side of the equation:
$$ \frac{1}{m+1} + \frac{1}{m(m+1)} $$ $$ \frac{m + 1}{m(m+1)} $$Now, let's simplify the expression:
$$ \frac{1}{m} $$It is now evident that the original equation:
$$ \frac{1}{m+1} + \frac{1}{m^2+m} \equiv \frac{1}{m} $$Is generally true, as the left-hand side simplifies to \( \frac{1}{m} \).
Thus, the algebraic generalisation provided does hold true for all values of \( m \).
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